2x^2-25-450=0

Solution for 2x^2-25-450=0 equation:

2x^2-25-450=0

We add all the numbers together, and all the variables

2x^2-475=0

a = 2; b = 0; c = -475;
Δ = b2-4ac
Δ = 02-4·2·(-475)
Δ = 3800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3800}=\sqrt{100*38}=\sqrt{100}*\sqrt{38}=10\sqrt{38}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{38}}{2*2}=\frac{0-10\sqrt{38}}{4}
=-\frac{10\sqrt{38}}{4}
=-\frac{5\sqrt{38}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{38}}{2*2}=\frac{0+10\sqrt{38}}{4}
=\frac{10\sqrt{38}}{4}
=\frac{5\sqrt{38}}{2}
$